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25=3.14(1.5^2)h
We move all terms to the left:
25-(3.14(1.5^2)h)=0
We calculate terms in parentheses: -(3.14(1.5^2)h), so:a = -3; b = 0; c = +25;
3.14(1.5^2)h
We multiply parentheses
3h^2
Back to the equation:
-(3h^2)
Δ = b2-4ac
Δ = 02-4·(-3)·25
Δ = 300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{300}=\sqrt{100*3}=\sqrt{100}*\sqrt{3}=10\sqrt{3}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{3}}{2*-3}=\frac{0-10\sqrt{3}}{-6} =-\frac{10\sqrt{3}}{-6} =-\frac{5\sqrt{3}}{-3} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{3}}{2*-3}=\frac{0+10\sqrt{3}}{-6} =\frac{10\sqrt{3}}{-6} =\frac{5\sqrt{3}}{-3} $
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